(1/x-3)+(1/x-3)=(16/x^2-9)

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Solution for (1/x-3)+(1/x-3)=(16/x^2-9) equation: 



(1/x-3)+(1/x-3)=(16/x^2-9)

We move all terms to the left:

(1/x-3)+(1/x-3)-((16/x^2-9))=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x^2-9))!=0

x∈R



We get rid of parentheses

1/x+1/x-((16/x^2-9))-3-3=0

We calculate fractions

We do not support expression: x^3

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